Optimal. Leaf size=167 \[ -\frac {4 a^4 (a \sin (e+f x))^{3/2}}{77 b f \sqrt {b \tan (e+f x)}}-\frac {2 a^2 (a \sin (e+f x))^{7/2}}{77 b f \sqrt {b \tan (e+f x)}}+\frac {2 (a \sin (e+f x))^{11/2}}{11 b f \sqrt {b \tan (e+f x)}}+\frac {8 a^6 \sqrt {\cos (e+f x)} F\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \sqrt {b \tan (e+f x)}}{77 b^2 f \sqrt {a \sin (e+f x)}} \]
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Rubi [A]
time = 0.15, antiderivative size = 167, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {2676, 2678,
2681, 2720} \begin {gather*} \frac {8 a^6 \sqrt {\cos (e+f x)} F\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \sqrt {b \tan (e+f x)}}{77 b^2 f \sqrt {a \sin (e+f x)}}-\frac {4 a^4 (a \sin (e+f x))^{3/2}}{77 b f \sqrt {b \tan (e+f x)}}-\frac {2 a^2 (a \sin (e+f x))^{7/2}}{77 b f \sqrt {b \tan (e+f x)}}+\frac {2 (a \sin (e+f x))^{11/2}}{11 b f \sqrt {b \tan (e+f x)}} \end {gather*}
Antiderivative was successfully verified.
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Rule 2676
Rule 2678
Rule 2681
Rule 2720
Rubi steps
\begin {align*} \int \frac {(a \sin (e+f x))^{11/2}}{(b \tan (e+f x))^{3/2}} \, dx &=\frac {2 (a \sin (e+f x))^{11/2}}{11 b f \sqrt {b \tan (e+f x)}}+\frac {a^2 \int (a \sin (e+f x))^{7/2} \sqrt {b \tan (e+f x)} \, dx}{11 b^2}\\ &=-\frac {2 a^2 (a \sin (e+f x))^{7/2}}{77 b f \sqrt {b \tan (e+f x)}}+\frac {2 (a \sin (e+f x))^{11/2}}{11 b f \sqrt {b \tan (e+f x)}}+\frac {\left (6 a^4\right ) \int (a \sin (e+f x))^{3/2} \sqrt {b \tan (e+f x)} \, dx}{77 b^2}\\ &=-\frac {4 a^4 (a \sin (e+f x))^{3/2}}{77 b f \sqrt {b \tan (e+f x)}}-\frac {2 a^2 (a \sin (e+f x))^{7/2}}{77 b f \sqrt {b \tan (e+f x)}}+\frac {2 (a \sin (e+f x))^{11/2}}{11 b f \sqrt {b \tan (e+f x)}}+\frac {\left (4 a^6\right ) \int \frac {\sqrt {b \tan (e+f x)}}{\sqrt {a \sin (e+f x)}} \, dx}{77 b^2}\\ &=-\frac {4 a^4 (a \sin (e+f x))^{3/2}}{77 b f \sqrt {b \tan (e+f x)}}-\frac {2 a^2 (a \sin (e+f x))^{7/2}}{77 b f \sqrt {b \tan (e+f x)}}+\frac {2 (a \sin (e+f x))^{11/2}}{11 b f \sqrt {b \tan (e+f x)}}+\frac {\left (4 a^6 \sqrt {\cos (e+f x)} \sqrt {b \tan (e+f x)}\right ) \int \frac {1}{\sqrt {\cos (e+f x)}} \, dx}{77 b^2 \sqrt {a \sin (e+f x)}}\\ &=-\frac {4 a^4 (a \sin (e+f x))^{3/2}}{77 b f \sqrt {b \tan (e+f x)}}-\frac {2 a^2 (a \sin (e+f x))^{7/2}}{77 b f \sqrt {b \tan (e+f x)}}+\frac {2 (a \sin (e+f x))^{11/2}}{11 b f \sqrt {b \tan (e+f x)}}+\frac {8 a^6 \sqrt {\cos (e+f x)} F\left (\left .\frac {1}{2} (e+f x)\right |2\right ) \sqrt {b \tan (e+f x)}}{77 b^2 f \sqrt {a \sin (e+f x)}}\\ \end {align*}
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Mathematica [A]
time = 0.77, size = 118, normalized size = 0.71 \begin {gather*} \frac {a^5 \left (\sqrt [4]{\cos ^2(e+f x)} (-22 \cos (e+f x)-17 \cos (3 (e+f x))+7 \cos (5 (e+f x)))+64 \cot (e+f x) F\left (\left .\frac {1}{2} \text {ArcSin}(\sin (e+f x))\right |2\right )\right ) \sqrt {a \sin (e+f x)} \tan ^2(e+f x)}{616 f \sqrt [4]{\cos ^2(e+f x)} (b \tan (e+f x))^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains complex when optimal does not.
time = 0.84, size = 181, normalized size = 1.08
method | result | size |
default | \(-\frac {2 \left (-7 \left (\cos ^{6}\left (f x +e \right )\right )+4 i \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \EllipticF \left (\frac {i \left (\cos \left (f x +e \right )-1\right )}{\sin \left (f x +e \right )}, i\right ) \sin \left (f x +e \right )+7 \left (\cos ^{5}\left (f x +e \right )\right )+13 \left (\cos ^{4}\left (f x +e \right )\right )-13 \left (\cos ^{3}\left (f x +e \right )\right )-4 \left (\cos ^{2}\left (f x +e \right )\right )+4 \cos \left (f x +e \right )\right ) \left (a \sin \left (f x +e \right )\right )^{\frac {11}{2}}}{77 f \left (\cos \left (f x +e \right )-1\right ) \cos \left (f x +e \right )^{2} \sin \left (f x +e \right )^{3} \left (\frac {b \sin \left (f x +e \right )}{\cos \left (f x +e \right )}\right )^{\frac {3}{2}}}\) | \(181\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.14, size = 150, normalized size = 0.90 \begin {gather*} \frac {2 \, {\left (2 \, \sqrt {2} \sqrt {-a b} a^{5} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right ) + 2 \, \sqrt {2} \sqrt {-a b} a^{5} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right ) + {\left (7 \, a^{5} \cos \left (f x + e\right )^{5} - 13 \, a^{5} \cos \left (f x + e\right )^{3} + 4 \, a^{5} \cos \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {b \sin \left (f x + e\right )}{\cos \left (f x + e\right )}}\right )}}{77 \, b^{2} f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (a\,\sin \left (e+f\,x\right )\right )}^{11/2}}{{\left (b\,\mathrm {tan}\left (e+f\,x\right )\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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